Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringMiscellaneousHard2 minPYQ_2015
PhysicsHardsingle choice

A string is stretched between fixed points separated by 75.0 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencier between these two. The lowest resonant frequency for this string is:NEET 2015 (Phase 2)

Options:

Answer:
C
Solution:

Two consecutive resonant frequencies for a string fixed at both ends will be

nv2l  and n+1v2l

⇒    n+1v2l-nv2l=420-315

v2l=105 Hz

Which is the minimum resonant frequency.

Stream:NEETSubject:PhysicsTopic:Wave on StringSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2015

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