The phase difference between two waves represented by y 1 = 1 0 − 6 sin [ 100 t + ( x /50 ) + 0.5 ] m y 1 = 1 0 − 6 cos [ 100 t + ( x /50 )] m where x is expressed in metres and t is expressed

Question

The phase difference between two waves represented by ​ y 1 ​ = 1 0 − 6 sin [ 100 t + ( x /50 ) + 0.5 ] m y 1 ​ = 1 0 − 6 cos [ 100 t + ( x /50 )] m ​ where x is expressed in metres and t is expressed in seconds is approximatelyNEET 2004

TestHub · Accepted Answer

Here y 1 ​ = 1 0 6 sin [ 100 t + ( 50 x ​ ) + 0.5 ] ​ and y 2 ​ = 1 0 − 6 cos [ 100 t + ( 50 x ​ ) ] = 1 0 − 6 sin [ 100 t + ( 50 x ​ ) + 2 π ​ ] = 1 0 − 6 sin [ 100 t + ( 50 x ​ ) + 1.57 ] ​ Then comparing the equation of y 1 ​ and y 2 ​ we get phase difference = 1.57 − 0.5 = 1.07

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