Physics - Wave on String Question with Solution | TestHub

The general equation of wave travelling in $x$-direction is given as $$y=A\sin \left[\frac{2\pi }{\lambda }(Vt-x)\right]$$ Where $A=0.2\mathrm{m},v=360{\mathrm{ms}}^{-1},\lambda =$ $60\mathrm{m}$ $\therefore$ The equation becomes $$\begin{array}{rl}& y=0.2\sin \left[\frac{2\pi }{60}(360t-x)\right]\\ & y=0.2\sin \left[2\pi \left(6t-\frac{x}{60}\right)\right]\end{array}$$