The angle between vector ( A → ) and ( A → - B → ) is :

tan ϕ = B sin 60 ° A - B cos 60 ° ϕ = tan - 1 B sin 60 ° A - B cos 60 ° = tan - 1 3 B 2 A - B

Physics - Vectors Question with Solution | TestHub

PhysicsVectorsAddition/SubtractionEasy2 minPYQ_2021

PhysicsEasysingle choice

The angle between vector $(\vec{A})$ and $(\vec{A} - \vec{B})$ is :

Answer:

Solution:

$\tan ϕ = \frac{B \sin 60 °}{A - B \cos 60 °}$

$ϕ = \tan^{- 1} (\frac{B \sin 60 °}{A - B \cos 60 °}) = \tan^{- 1} (\frac{\sqrt{3} B}{2 A - B})$

Stream:JEESubject:PhysicsTopic:VectorsSubtopic:Addition/Subtraction

⏱ 2mℹ️ Source: PYQ_2021

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