Resultant of two vectors P and Q is of magnitude R 1 . If direction of Q is reversed, the resultant is of magnitude R 2 . The value of ( R 1 2 + R 2 2 ) is [ cos ( π − θ ) = − cos θ ]

Question

Resultant of two vectors P and Q ​ is of magnitude R 1 ​ . If direction of Q ​ is reversed, the resultant is of magnitude R 2 ​ . The value of ( R 1 2 ​ + R 2 2 ​ ) is [ cos ( π − θ ) = − cos θ ]

TestHub · Accepted Answer

Given, P + Q = R After reversing direction of R , we gel − R = − P − Q S = − P − Q ​ So let angle between P and Q be Q So resultants. R 2 = P 2 + Q 2 + 2 PQ cos θ S 2 = P 2 + Q 2 − 2 PQ cos θ ( 2 ) − ( 1 ) ​ ​ Adthing equation (1) and (2) R 2 + S 2 = 2 ( P 2 + Q 2 ) So, the correct answer is R 2 + s 2 = 2 ( p 2 + Q 2 )

Physics - Vectors Question with Solution | TestHub

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