The angle subtended by the vector A = 4  ^ + 3  ^ + 12 k ^ with the x -axis is

A = 4 i + 3 j + 12 k p = i cos θ ∣ A ∣∣ B ∣ ∣ A ⋅ B ⇒ 16 + 9 + 144 × 1 4 θ ⇒ cos ′ 1/13

Physics - Vectors Question with Solution | TestHub

PhysicsVectorsAddition/SubtractionEasy2 minPYQ_2020

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The angle subtended by the vector $A = 4 \overset{}{^} + 3 \overset{}{^} + 12 \hat{k}$ with the $x$ -axis is

Answer:

Solution:

$A = 4 i + 3 j + 12 k$ $p = i$ $cos θ \frac{∣ A \cdot B}{∣ A ∣∣ B ∣} \Rightarrow \frac{4}{16 + 9 + 144 \times 1}$ $θ \Rightarrow cos^{'} 1/13$

Stream:MHT_CETSubject:PhysicsTopic:VectorsSubtopic:Addition/Subtraction

⏱ 2mℹ️ Source: PYQ_2020

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