Let the two forces have equal magnitude ' A ′ . If the magnitude of the resultant is 3 2 A then the angle between those two forces is

rexultant = 2 A /3 2 A /3 = A 2 + A 2 + 2 AA cos ϕ 9 4 A 2 = 2 A 2 + 2 A 2 cos ϕ 9 4 A 2 − 18 A 2 = 2 A 2 cos ϕ cos ϕ = 9 × 2 − 14 ⇒ ϕ = cos − 1 (-7 / 9)

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Physics - Vectors Question with Solution | TestHub

PhysicsVectorsAddition/SubtractionEasy2 minPYQ_2020

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Let the two forces have equal magnitude ' $A^{'}$ . If the magnitude of the resultant is $\frac{2 A}{3}$ then the angle between those two forces is

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rexultant $= 2 A /3$ $2 A /3 = A^{2} + A^{2} + 2 AA cos ϕ$ $\frac{4 A ^{2}}{9} = 2 A^{2} + 2 A^{2} cos ϕ$ $\frac{4 A ^{2} - 18 A ^{2}}{9} = 2 A^{2} cos ϕ$ $cos ϕ = \frac{- 14}{9 \times 2} \Rightarrow ϕ =$ $cos^{- 1}$ (-7 / 9)

Stream:MHT_CETSubject:PhysicsTopic:VectorsSubtopic:Addition/Subtraction

⏱ 2mℹ️ Source: PYQ_2020

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