The position vector of a particle is r → = 3 i ^ + 4 j ^ metre and its angular velocity ω → = j ^ + 2 k ^ rad s - 1 then its linear velocity is i n m s - 1

The velocity can be computed using, v → = ω → × r → ω → × r → = i ^ j ^ k ^ 0 1 2 3 4 0 = - 8 i ^ + 6 j ^ - 3 k ^

Start Free Mock LoginAlready registered? Login here

Physics - Vectors Question with Solution | TestHub

PhysicsVectorsMultiplication of vectorsEasy2 minPYQ_2020

PhysicsEasysingle choice

The position vector of a particle is $\vec{r} = (3 \hat{i} + 4 \hat{j}) metre$ and its angular velocity $\vec{ω} = (\hat{j} + 2 \hat{k}) rad s^{- 1}$ then its linear velocity is $(i n m s^{- 1})$

Options:

Answer:

Solution:

The velocity can be computed using, $\vec{v} = \vec{ω} \times \vec{r}$

$\vec{ω} \times \vec{r} = |\begin{matrix} \hat{i} & \hat{j} & \hat{k} \\ 0 & 1 & 2 \\ 3 & 4 & 0 \end{matrix}| = - 8 \hat{i} + 6 \hat{j} - 3 \hat{k}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:VectorsSubtopic:Multiplication of vectors

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...