The potential energy of a particle varies with distance x from a fixed point as U = x + B 2 A x where A and B are constants. Then the dimension of AB 2 is -

Question

The potential energy of a particle varies with distance x from a fixed point as U = x + B 2 A x ​ ​ where A and B are constants. Then the dimension of AB 2 is -

TestHub · Accepted Answer

dim [ B ] = dim [ x ​ ] = L 1/2 & dim [ A ] = [ U x ​ ] = [ ( M L 2 T − 2 ) L 1/2 ] = [ M L 5/2 T − 2 ] ⇒ dim [ A B 2 ] = [ M L 5/2 T − 2 ] [ L ] = [ M L 7/2 T − 2 ]

Physics - Unit & Dimension Question with Solution | TestHub

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