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PhysicsUnit & DimensionMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

In the formula $P = Q^{2} Z, P$ is power and $Q$ is charge. The dimensions of $Z$ are

Answer:

Solution:

$[Z] = \frac{[ P ]}{[ Q ^{2} ]}$
$= \frac{[ M L ^{2} T ^{- 3} ]}{[ Q ^{2} ]}$
$= [M L^{2} T^{- 3} Q^{- 2}]$ .

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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