Consider two physical quantities A and B related to each other as E = At B − x 2 where E , x and t have dimensions of energy, length and time respectively. The dimension of A B is

Dimensions of x 2 = Dimensions of B = L 2 . Dimensions of A = tE x 2 = TM L 2 T − 2 L 2 = M − 1 T . Therefore, dimensions of A B = L 2 M − 1 T .

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PhysicsUnit & DimensionMiscellaneousEasy2 minQB

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Consider two physical quantities $A$ and $B$ related to each other as $E = \frac{B - x ^{2}}{At}$ where $E, x$ and $t$ have dimensions of energy, length and time respectively. The dimension of $A B$ is

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Answer:

Solution:

Dimensions of $x^{2}$ = Dimensions of $B = L^{2}$ .

Dimensions of $A = \frac{x ^{2}}{tE} = \frac{L ^{2}}{TM L ^{2} T ^{- 2}} = M^{- 1} T$ .

Therefore, dimensions of $A B = L^{2} M^{- 1} T$ .

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

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