Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

The physical quantity having the dimensions $[M^{- 1} L^{- 3} T^{3} A^{2}]$ is

Options:

Answer:

Solution:

From $H = I^{2} Rt, R$
$= \frac{[ H ]}{[ I ^{2} t ]}$
$= \frac{[ M L ^{2} T ^{- 2} ]}{[ A ^{2} T ]}$
$= [M L^{2} T^{- 3} A^{- 2}]$
Similarly, conductivity $σ = \frac{l}{R A}$ has dimensions
$\frac{[ L ]}{[ M L ^{2} T ^{- 3} A ^{- 2} ] [ L ^{2} ]}$
$= [M^{- 1} L^{- 3} T^{3} A^{2}]$ .

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...