In the Berthelot equation ( p + T V 2 a ) ( V − b ) = RT , where p is pressure, V volume and T temperature, the dimensions of a are

[ T ] [ V 2 ] [ a ] = [ p ] , so [ a ] = [ M L − 1 T − 2 ] [ K ] [ L 6 ] = [ M L 5 T − 2 K ] .

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PhysicsUnit & DimensionMiscellaneousMedium2 minQB

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In the Berthelot equation $(p + \frac{a}{T V ^{2}}) (V - b) = RT$ , where $p$ is pressure, $V$ volume and $T$ temperature, the dimensions of $a$ are

Answer:

Solution:

$\frac{[ a ]}{[ T ] [ V ^{2} ]} = [p]$ , so
$[a] = [M L^{- 1} T^{- 2}] [K] [L^{6}]$
$= [M L^{5} T^{- 2} K]$ .

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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