Physics - Unit & Dimension Question with Solution | TestHub

$1\mathrm{N}=10^5$ dyne and
$1{\mathrm{m}}^2=10^4{\mathrm{cm}}^2$, so
$2.0\times 10^{11}\frac{\mathrm{N}}{{\mathrm{m}}^2}$
$=\frac{2.0\times 10^{11}\times 10^5}{10^4}\frac{\text{ dyne }}{{\mathrm{cm}}^2}$
$=2.0\times 10^{12}\frac{\text{ dyne }}{{\mathrm{cm}}^2}$.