The potential energy of a particle moving along x -direction varies as V = x + B A x 2 . The dimensions of B A 2 are:NEET 2024 (Re-NEET)

V = x + B A x 2 As per homogeneous rule B = L ML 2 T − 2 = L 1/2 A L 2 A = ML 1/2 T − 2 B A 2 = L 1/2 M 2 L T − 4 = M 2 L 1/2 T − 4

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Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousMedium2 minPYQ_2024

PhysicsMediumsingle choice

The potential energy of a particle moving along $x$ -direction varies as $V = \frac{A x ^{2}}{x + B}$ . The dimensions of $\frac{A ^{2}}{B}$ are:NEET 2024 (Re-NEET)

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$V = \frac{A x ^{2}}{x + B}$ As per homogeneous rule $B = L$ $ML^{2} T^{- 2} = \frac{A L ^{2}}{L ^{1/2}}$ $A = ML^{1/2} T^{- 2}$ $\frac{A ^{2}}{B} = \frac{M ^{2} L T ^{- 4}}{L ^{1/2}} = M^{2} L^{1/2} T^{- 4}$

Stream:NEETSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2024

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