Physics - Unit & Dimension Question with Solution | TestHub

Energy density in magnetic field is given by $u=\frac{B^2}{2{\mu }_0}$. Therefore, dimensions of $\frac{B^2}{{\mu }_0}$ will be equal to the dimensions of energy per unit volume.

$\left[\frac{B^2}{{\mu }_0}\right]=\left[u\right]=\frac{\left[{\mathrm{ML}}^2{\mathrm{T}}^{-2}\right]}{\left[{\mathrm{L}}^3\right]}=\left[{\mathrm{ML}}^{-1}{\mathrm{T}}^{-2}\right]$