If E and G respectively denote energy and gravitational constant, then E G has the dimensions of:NEET 2021

Dimensional Formulas, Energy, [ E ] = M 1 L 2 T - 2 Gravitational constant [ G ] = F r 2 M 2 = M 1 L 1 T - 2 × L 2 M 2 [ G ] = M - 1 L 3 T - 2 Now, E G = M L 2 T - 2 M - 1 L 3 T - 2 = M 2 L - 1 T 0 Correct option (3)

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Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2021

PhysicsEasysingle choice

If $E$ and $G$ respectively denote energy and gravitational constant, then $\frac{E}{G}$ has the dimensions of:NEET 2021

Options:

Answer:

Solution:

Dimensional Formulas,

Energy, $[E] = M^{1} L^{2} T^{- 2}$

Gravitational constant

$[G] = [\frac{F r^{2}}{M^{2}}] = \frac{M^{1} L^{1} T^{- 2} \times L^{2}}{M^{2}}$

$[G] = M^{- 1} L^{3} T^{- 2}$

Now,

$[\frac{E}{G}] = \frac{M L^{2} T^{- 2}}{M^{- 1} L^{3} T^{- 2}} = M^{2} L^{- 1} T^{0}$

Correct option (3)

Stream:NEETSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2021

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