Physics - Unit & Dimension Question with Solution | TestHub

Given that

$\mathrm{S}=2\mathrm{cal}/{\mathrm{cm}}^2/\min$

But as$1 \mathrm{cal}=4.18\mathrm{J},1 \mathrm{cm}={10}^{-2}\mathrm{m}$and$1 \min =60 \mathrm{s}$

$\text{S}=\frac{2\times \text{4.18 J}}{{\left({\text{10}}^{-2}\text{m}\right)}^2\left(\text{60s}\right)}$

$\approx \text{1.4}\times {\text{10}}^3\frac{\text{J}}{{\text{m}}^2\text{s}}\text{or}\text{S}=\text{1.4}{\text{kW/m}}^2$