Physics - Unit & Dimension Question with Solution | TestHub

$[S]=[L],[t]=[T],[P]=\left[M{L}^{-1}{T}^{-2}\right]$ Also. $[C]=\left[T^2\right]\dots (i)$ Now, $\left[M{L}^{-1}{T}^{-2}\right]=\frac{\left[T^2\right]}{[D][L]}$ $\Rightarrow [D]=\left[\begin{array}{l}{M}^{-1}{L}^0{T}^4\end{array}\right]\dots (ii)$ Now $(ii/i)\Rightarrow \frac{[D]}{[C]}=\frac{\left[M^{-1}{L}^0{T}^4\right]}{\left[T^2\right]}$ $=\left[L^0{M}^{-1}{T}^2\right]$