Force acting on a particle is given by F = A - x B t , where x is in metre and t is in seconds. The dimensions of B is -

F = ma, we get F = M 1 [ L 1 T - 2 ] The dimension of force = [ MLT - 2 ] F = A - x B t B = [ L ] M L T - 2 [ T ] = M - 1 T 1

Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

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Force acting on a particle is given by $F = \frac{A - x}{B t}$ , where x is in metre and t is in seconds. The dimensions of B is -

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Answer:

Solution:

F = ma, we get

$F = [M^{1}] [L^{1} T^{- 2}]$

The dimension of force = $[{MLT}^{- 2}]$

$[F] = \frac{[A - x]}{[B] [t]}$

$[B] = \frac{[L]}{[M L T^{- 2}] [T]} = [M^{- 1} T^{1}]$

Stream:NTA_ABHYASSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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