Physics - Unit & Dimension Question with Solution | TestHub

Given, Dimension of $B$ is $\left[M^{0}L{T}^{-1}\right]$ \& $C$ is $\left[M^{0}L{T}^0\right]$ Now we know that, same dimensions can be added and the results we get are in same dimensions. So, dimension of $A=B=\left[M^{0}L{T}^{-1}\right]$ Let, the dimension of $D$ \& $E$ is $\left[M^X{L}^Y{T}^Z\right]$ $\therefore M^{0}L{T}^{-1}=\frac{M^{0}L{T}^0}{M^X{L}^Y{T}^Z}$ $\Rightarrow M^X{L}^Y{T}^Z=M^0{L}^0{T}^1$ $X=0,Y=0\&Z=1$ So, the dimension of $D$ \& $E$ is $[T]$