Physics - Unit & Dimension Question with Solution | TestHub

Correct option is D angle. $[\mathrm{E}]=\left[{\mathrm{ML}}^2{\mathrm{T}}^{-2}\right],[\mathrm{m}]$ $=[\mathrm{M}][\mathrm{I}]=\left[{\mathrm{ML}}^2{\mathrm{T}}^{-1}\right],[\mathrm{G}]=\left[{\mathrm{M}}^{-1}{\mathrm{L}}^3{\mathrm{T}}^{-2}\right]$ $\therefore \left[\frac{{\mathrm{El}}^2}{{\mathrm{m}}^5{\mathrm{G}}^2}\right]=\frac{\left[{\mathrm{ML}}^2{\mathrm{T}}^{-2}\right]\left[{\mathrm{M}}^2{\mathrm{L}}^4{\mathrm{T}}^{-2}\right]}{\left[{\mathrm{M}}^5\right]\left[{\mathrm{M}}^{-2}{\mathrm{L}}^6{\mathrm{T}}^{-4}\right]}$ $=\left[{\mathrm{M}}^0{\mathrm{L}}^0{\mathrm{T}}^0\right]$ As angle has no dimensions, therefore $\frac{{\mathrm{El}}^5}{{\mathrm{m}}^5{\mathrm{G}}^2}$ has the same dimensions as that of angle.