If the length of rod A is 3.25 ± 0.01 c m and that of B is 4.19 ± 0.01 c m , then the rod B is longer than rod A by

Given, length of rod A is L A = 3.25 ± 0.01 Of B is L B = 4.19 ± 0.01 Then, the rod B is longer than rod A by a length ∆ l = L B - L A ∆ l = 4.19 ± 0.01 - 3.25 ± 0.01 ∆ l = 0.94 ± 0.02 c m

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Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

If the length of rod $A$ is $(3.25 \pm 0.01) c m$ and that of $B$ is $(4.19 \pm 0.01) c m,$ then the rod $B$ is longer than rod $A$ by

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Answer:

Solution:

Given, length of rod $A$ is

$L_{A} = 3.25 \pm 0.01$

Of B is $L_{B} = 4.19 \pm 0.01$

Then, the rod B is longer than rod A by a length

$∆ l = L_{B} - L_{A}$

$∆ l = (4.19 \pm 0.01) - (3.25 \pm 0.01)$

$∆ l = (0.94 \pm 0.02) c m$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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