Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

If speedV,accelerationAand forceFare considered as fundamental units, the dimension of Young's modulus will be:

Options:

Answer:
D
Solution:

LetY=fV, F, A

Y=KVxFyAz, KUnit less

Y=VxFyAz

ML-1T-2=LT-1xMLT-2yLT-2z

ML-1T-2=MyLx+y+zT-x-2y-2z

  y=1, x+y+z=-1; -x-2y-2z=-2

x+z=-2  x+2y+2z=2

z=2, x=-4  x+2z=0

Y=V-4A2F

Stream:NTA_ABHYASSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous
2mℹ️ Source: PYQ_2020

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