Physics - Unit & Dimension Question with Solution | TestHub

The dimensions of Planck’s constant,
$\left[h\right]=\frac{\left[E\right]}{\left[v\right]}=\frac{\left[M{L}^2{T}^{-2}\right]}{\left[M^0{L}^0{T}^{-1}\right]}=\left[M{L}^2{T}^{-1}\right]$
And that moment of inertia,
$\left[l\right]=\left[M\right]{\left[R\right]}^2=\left[M\right]{\left[L\right]}^2=\left[M{L}^2{T}^0\right]$
$\therefore \frac{\left[h\right]}{\left[l\right]}=\frac{\left[M{L}^2{T}^{-1}\right]}{\left[M{L}^2{T}^0\right]}=\left[T^{-1}\right]=\left[v\right]$