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PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2017
PhysicsEasysingle choice

TimeT, velocityCand angular momentumhare chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be:

Options:

Answer:
A
Solution:

MTxCyhz
M1L0T0=T1xL1T-1yM1L2T-1z
[M1 L0T0]=[Mz Ly+2zTx-y-z]]
z=1
y+2z=0 , x-y-z=0
solving
y=-2
andx=-1
M T-1 C-2 h1

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous
2mℹ️ Source: PYQ_2017

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