Physics - Unit & Dimension Question with Solution | TestHub

Resistance $R=\frac{\text{ potential difference }}{\text{ current }}=\frac{V}{i}=\frac{W}{qi}$ ( $\because$ Potential difference is equal to work done per unit charge) So, Dimensions of $R$ $\frac{[Dimensionsofwork]}{[Dimensionsofcharge][Dimensionsofcurrent]}$ $=\frac{\left[{\mathrm{ML}}^2{\mathrm{T}}^{-2}\right]}{[\mathrm{IT}][\mathrm{I}]}=\left[{\mathrm{ML}}^2{\mathrm{T}}^{-3}{\mathrm{I}}^{-2}\right]$