Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2009

PhysicsEasysingle choice

The dimensions of specific resistance are

Answer:

Solution:

Specific resistance $ρ = \frac{R A}{l}$ $= [ML^{2} T^{- 3} A^{- 2}] [L] = [ML^{3} T^{- 3} A^{- 2}]$

Stream:AIIMSSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2009

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