Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveWavesMedium2 minQB

PhysicsMediumnumerical

The apparent frequencies of a source on approach and recession differ by 4% of its natural frequency. Find the source speed ( $v = 340$ m/s).

Answer:

6.80

Solution:

$0.04 u^{2} + 680 u - 4624 = 0$ gives $u = 6.80$ m/s.

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Waves

⏱ 2mℹ️ Source: QB

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