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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveWavesMedium2 minQB

PhysicsMediumnumerical

The difference between the apparent frequency of a source of sound as perceived by an observer during its approach and recession is 2% of the natural frequency of the source. Find the velocity of the source. Take the velocity of sound as 350 m/s.

Answer:

3.50

Solution:

$\frac{v}{v - u} - \frac{v}{v + u} = 0.02$ gives $\frac{2 uv}{v ^{2} - u ^{2}} = 0.02$ . For $u ≪ v$ : $u \approx 0.01 v = 3.5$ m/s.

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Waves

⏱ 2mℹ️ Source: QB

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