A person standing between two parallel cliffs fires a gun and hears two echoes, first echo after 1 second and second echo after 3 second. The distance between the two cliffs is (The velocity of sound

Question

A person standing between two parallel cliffs fires a gun and hears two echoes, first echo after 1 second and second echo after 3 second. The distance between the two cliffs is (The velocity of sound = 330 m/s)

TestHub · Accepted Answer

Let the distance of the person from the first cliff be $d_{1}$ and from the second cliff be $d_{2}$ .

The time taken to hear the first echo is $t_{1} = 1$ s. The sound travels to the first cliff and back, so the distance covered is $2 d_{1}$ .

$2 d_{1} = v \times t_{1}$

$2 d_{1} = 330 \times 1 = 330$ m

$d_{1} = 165$ m

The time taken to hear the second echo is $t_{2} = 3$ s. The sound travels to the second cliff and back, so the distance covered is $2 d_{2}$ .

$2 d_{2} = v \times t_{2}$

$2 d_{2} = 330 \times 3 = 990$ m

$d_{2} = 495$ m

The total distance between the two cliffs is $d = d_{1} + d_{2}$ .

$d = 165 + 495 = 660$ m

Answer: $660$ m

Physics - Sound Wave Question with Solution | TestHub

Options:

Doubts & Discussion