Physics - Sound Wave Question with Solution | TestHub

Let $L$ be the length of the pipe and $v$ be the velocity of sound in air.

The time taken by the sound wave to travel from the open end to the closed end is given by $t=\frac{L}{v}$.

This gives $L=vt$.

For a pipe closed at one end, the fundamental frequency of vibration is given by $n=\frac{v}{4L}$.

Substituting $L=vt$ in the above equation, we get:

$n=\frac{v}{4(vt)}=\frac{1}{4t}=(4t{)}^{-1}$

Answer: $(4t{)}^{-1}$