Physics - Sound Wave Question with Solution | TestHub

For an open end organ pipe, antinodes are formed at both the open ends.

In the fundamental mode of vibration, the length of the pipe is $L=\frac{\lambda }{2}$.

$\Rightarrow \lambda =2L$

The fundamental frequency is given by $n=\frac{V}{\lambda }=\frac{V}{2L}$.

In an open organ pipe, the frequencies of higher modes of vibration are integral multiples of the fundamental frequency, i.e., $n,2n,3n,\dots$

Thus, all harmonics are present.

Answer: $\frac{\mathrm{V}}{2\mathrm{L}}$ and all harmonics are present.