Physics - Sound Wave Question with Solution | TestHub

The apparent frequency $f^{\prime }$ according to the Doppler effect is given by:

$f^{\prime }=f\left(\frac{V-v_o}{V-v_s}\right)$

where $v_o$ is the velocity of the observer moving away from the source, and $v_s$ is the velocity of the source moving towards the observer.

Given $v_o=\frac{V}{5}$ and $v_s=\frac{V}{3}$.

Substituting the values:

$f^{\prime }=f\left(\frac{V-\frac{V}{5}}{V-\frac{V}{3}}\right)$

$f^{\prime }=f\left(\frac{\frac{4V}{5}}{\frac{2V}{3}}\right)$

$f^{\prime }=f\left(\frac{4}{5}\times \frac{3}{2}\right)$

$f^{\prime }=\frac{6}{5}f$

Answer: $\frac{6}{5}\mathrm{f}$