In a closed organ pipe, the frequency of fundamental note is 30 Hz . A certain amount of water is now poured in the organ pipe so that the fundamental frequency is increased to 110 Hz . If the organ p

Question

In a closed organ pipe, the frequency of fundamental note is 30 Hz . A certain amount of water is now poured in the organ pipe so that the fundamental frequency is increased to 110 Hz . If the organ pipe has a cross-sectional area of 2 cm 2 , the amount of water poured in the organ tube is ________ g . (Take speed of sound in air is 330 m s - 1 )

TestHub · Accepted Answer

Fundamental frequency for closed organ pipe in the first part:

$\frac{V}{4 l_{1}} = 30 \Rightarrow l_{1} = \frac{11}{4} m$

Similarly, for second part:

$\frac{V}{4 l_{2}} = 110 \Rightarrow l_{2} = \frac{3}{4} m$

Therefore, change in length $Δ l = 2 m$

Change in volume $= AΔ l = 400 {cm}^{3}$

$M = 400 g; (∵ ρ = 1 g {cm}^{- 3})$

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