Physics - Sound Wave Question with Solution | TestHub

$$\mathrm{v}=\mathrm{n}\lambda$$ Since, both the sound sources are at same temperature, velocity of sound in both cases would be the same. $$\begin{array}{rl}& \therefore \mathrm{v}=\left(50{\mathrm{n}}_{\mathrm{l}}\right)\mathrm{cm}/\mathrm{s}.....(i)\\ & \mathrm{v}=\left(50.5{\mathrm{n}}_2\right)\mathrm{cm}/\mathrm{s}....(ii)\\ & \frac{{\mathrm{n}}_1}{{\mathrm{n}}_2}=\frac{50.5}{50}....[From(i)and(ii)]\\ & \therefore \frac{{\mathrm{n}}_1-{\mathrm{n}}_2}{{\mathrm{n}}_2}=\frac{50.5-50}{50}\\ & \end{array}$$ $\begin{array}{ll}\therefore & \frac{6}{{\mathrm{n}}_2}=\frac{0.50}{50}=\frac{1}{100}\dots .\left(\because {\mathrm{n}}_1-{\mathrm{n}}_2=6\mathrm{Hz}\right)\\ \therefore & {\mathrm{n}}_2=600\mathrm{Hz}\\ \therefore & \mathrm{v}=\frac{50.5\times 600}{100}\mathrm{m}/\mathrm{s}\dots [\text{ From (ii) }]\\ \therefore & \mathrm{v}=303\mathrm{m}/\mathrm{s}\end{array}$