A sound of frequency 480 Hz is emitted from the stringed instrument. The velocity of sound in air is 320 m / s . After completing 180 vibrations, the distance covered by a wave is

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Given: v = 320 m / s , f = 480 Hz , N = 180 v = f λ ∴ λ = f v ​ Substituting the values, we get λ = 480 320 ​ = 3 2 ​ ∴ The total distance covered after 180 vibrations is ​ D = N × λ D = 180 × 3 2 ​ D = 120 m ​

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