Physics - Sound Wave Question with Solution | TestHub

Let the intensities of the two waves be $I_1$ and $I_2$. Given: $I_1:I_2=49:16$ Therefore, the ratio of maximum and minimum intensities is given by, $\frac{I_{\max }}{I_{\min }}={\left(\frac{A_1+A_2}{A_1-A_2}\right)}^2={\left(\frac{\sqrt{I_1}+\sqrt{I_2}}{\sqrt{I_1}-\sqrt{I_2}}\right)}^2={\left(\frac{7+4}{7-4}\right)}^2=\frac{121}{9}$