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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveMiscellaneousEasy2 minPYQ_2022

PhysicsEasysingle choice

Two waves are superimposed whose ratio of intensities is $9 : 1$ . The ratio of maximum and minimum intensity is

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Solution:

Given, the ratio of intensities, we can obtain ratio of amplitudes of the waves: $\frac{I _{1}}{I _{1}} = (\frac{a _{1}}{a _{2}})^{2} = \frac{9}{1} \Rightarrow \frac{a _{1}}{a _{2}} = \frac{3}{1}$ $\frac{I _{m a x}}{I _{m i n}} = \frac{( a _{1} + a _{2} ) ^{2}}{( a _{1} - a _{2} ) ^{2}} = \frac{( 3 a _{2} + a _{2} ) ^{2}}{( 3 a _{2} - a _{2} ) ^{2}} = (\frac{4 a _{2}}{2 a _{2}})^{2} = \frac{4}{1}$

Stream:MHT_CETSubject:PhysicsTopic:Sound WaveSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2022

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