Start Free Mock LoginAlready registered? Login here

Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveDopler's effectHard2 minPYQ_2021

PhysicsHardsingle choice

A source producing sound of frequency $170 Hz$ is approaching a stationary observer with a velocity $17 ms^{- 1}$ . The apparent change in the wavelength of sound heard by the observer is (speed of sound in air $= 340 ms^{- 1}$ )

Options:

Answer:

Solution:

$λ = \frac{v}{n} = \frac{340}{170} = 2 m, n^{'} = \frac{340}{340 - 17} \times 170 n^{'} = 178.9 Hz Now λ^{'} = \frac{v}{n ^{'}} = \frac{340}{178.9} = 1.9 \Rightarrow λ - λ^{'} = 2 - 1.9 = 0.1 m$

Stream:VITEEESubject:PhysicsTopic:Sound WaveSubtopic:Dopler's effect

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...