The frequencies of three tuning forks A, B and C are related as n A n B n C . Which the forks A and B are sounded together, the number of beats produced per second is ' n 1 '. Wh

Question

The frequencies of three tuning forks A, B and C are related as $n_{A} > n_{B} > n_{C}$ . Which the forks $A$ and $B$ are sounded together, the number of beats produced per second is ' $n_{1}$ '. When forks $A$ and $C$ are sounded together the number of beats produced per second is ' $n_{2}$ '. How may beats are produced per second when forks B and $C$ are sounded together?

Options:

Answer:

C

Solution:

$n_{A} - n_{B} = n_{1}$ $n_{A} - n_{C} = n_{2}$ Subtracting Eq. (i) from eq. (ii) $n_{B} - n_{C} = n_{2} - n_{1}$

TestHub · Accepted Answer

n A ​ − n B ​ = n 1 ​ n A ​ − n C ​ = n 2 ​ Subtracting Eq. (i) from eq. (ii) n B ​ − n C ​ = n 2 ​ − n 1 ​

Physics - Sound Wave Question with Solution | TestHub

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