A tuning fork is vibrating at 250 Hz . The length of the shortest closed organ pipe that will resonate with the tuning fork will be _____ cm . (Take speed of sound in air as 340 m s - 1 )

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TestHub · Accepted Answer

For closed organ pipe f = ( 2 n + 1 ) v 4 l for minimum length, n = 0 f 0 = v 4 l ⇒ l = v 4 f 0 = 340 4 × 250 = 34 cm

Physics - Sound Wave Question with Solution | TestHub

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