Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveStanding waveHard2 minPYQ_2020

PhysicsHardsingle choice

A light string is tied at one end to a fixed support and to a heavy string of equal length $L$ at the other end $A$ as shown in the figure ( Total length of both strings combined is $2 L$ ). A block of mass $M$ is tied to the free end of heavy string. Mass per unit length of the strings are $μ$ and $16 μ$ and tension is $T$ . Find lowest positive value of frequency such that junction point $A$ is a node.

Options:

Answer:

Solution:

$f_{1} = \frac{n_{1}}{2 L} \sqrt{\frac{T}{μ}}$ , $f_{2} = \frac{n_{2}}{2 L} \sqrt{\frac{T}{16 μ}}$

$f_{1} = f_{2} \Rightarrow n_{1} = \frac{n_{2}}{4}$

$n_{1} = 1$ , $n_{2} = 4$

$f_{\min} = (\frac{1}{2 L}) \sqrt{\frac{T}{μ}}$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2020

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