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PhysicsSound WaveMiscellaneousMedium2 minPYQ_2020

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If the temperature is raised by $1 K$ from $300 K$ , the percentage change in the speed of sound in the gaseous mixture is [ $R = 8.314 J {mol}^{- 1} K^{- 1}$ ]

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Answer:

Solution:

From $v = \sqrt{\frac{γ R T}{M}}$

$\frac{∆ v}{v} = \frac{1}{2} \frac{∆ T}{T}$

$\frac{∆ v}{v} \times 100 = \frac{1}{2} (\frac{∆ T}{T}) \times 100$

$= \frac{1}{2} \times \frac{1}{300} \times 100 = 0.167 %$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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