Physics - Sound Wave Question with Solution | TestHub

Here, S = 2 km = 2,000 m ; v_air= 330 m s^-1

Therefore, time taken by sound to travel through air,

${\text{t}}_{\text{air}}=\frac{\text{S}}{{\text{v}}_{\text{air}}}=\frac{\text{2,000}}{\text{330}}=\text{6.06 s}$

As the two sounds (through air and iron rails) are heard at an interval of 5.2 s, time taken by sound to travel through iron rails,

t_iron= t_air- 5.2

= 6.06 - 5.2 = 0.86 s

Therefore, velocity of sound in iron,

${\text{V}}_{\text{iron}}=\frac{\text{S}}{{\text{t}}_{\text{iron}}}=\frac{\text{2,000}}{\text{0.86}}$

= 2,325.6 m s^-1