Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveStanding waveHard2 minPYQ_2020

PhysicsHardsingle choice

A composite wire of length $2 L$ is made by joining two different wires $A$ and $B$ having the same length, made of the same material but of different radii $r$ and $2 r$ respectively. The composite wire is vibrating at such a frequency, that the junction of the two wires form a node. If the number of antinodes in the wire $A$ is $p$ and that in the wire $B$ is $q$ , then the ratio $p : q$ is

Options:

Answer:

Solution:

$f_{1} = \frac{n}{2 ℓ} \sqrt{\frac{T}{ρA}}; f_{2} = \frac{m}{2 ℓ} \sqrt{\frac{T}{ρ 4 A}}$
Given $f_{1} = f_{2}$
$\frac{f_{1}}{f_{2}} = \frac{n}{m} \times 2$

$\frac{n}{m} = \frac{1}{2}$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2020

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