An open pipe is in resonance in 2 nd harmonic with frequency f 1 . Now one end of the tube is closed and frequency is increased to f 2 such that the resonance again occurs in n th harmonic. Choose the correct option.

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PhysicsSound WaveStanding waveMedium2 minPYQ_2020

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An open pipe is in resonance in 2^ndharmonic with frequency f₁. Now one end of the tube is closed and frequency is increased tof₂such that the resonance again occurs in n^thharmonic. Choose the correct option.

Options:

Answer:

Solution:

$f_{1} = \frac{v}{l}$ (2nd harmonic of open pipe)

$f_{2} = n (\frac{v}{4 l})$ (nth harmonic of closed pipe)

Here, n is odd and $f_{2} > f_{1}$

It is possible when n = 5

because with n = 5

$f_{2} = \frac{5}{4} (\frac{v}{l}) = \frac{5}{4} f_{1}$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2020

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