When a source of frequency f 0 moves away from a stationary observer with a certain velocity, an apparent frequency f ' is observed. When it moves with the same speed towards the observer, the observe

Question

When a source of frequency f 0 moves away from a stationary observer with a certain velocity, an apparent frequency f ' is observed. When it moves with the same speed towards the observer, the observed frequency is 1.2 f ' . If the velocity of sound is v , then the actual frequency f 0 is

TestHub · Accepted Answer

When source moves away from a stationary observer $f^{'} = f_{0} (\frac{v}{v + u})$

When source moves with the same speed towards the observer $1.2 f^{'} = f_{0} (\frac{v}{v - u})$

$∴ u = \frac{v}{11}$

$∴ f_{0} = f^{'} (1 + \frac{u}{v}) = \frac{12}{11} f^{'}$

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