A closed organ pipe of length L L 4 is in resonance with a tuning fork. If a hole is made in the pipe at a distance L/4 from closed-end, it will be in resonance again, when :

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Standing wave cannot be formed. It becomes combination of two pipes one closed and other open pipe. They will not satisfy the condition of standing wave simultaneously.

$\frac{n_{1} V}{2 (\frac{3 L}{4})} = \frac{n_{2} V}{4 (\frac{L}{4})}$

$\frac{n_{1} 2 V}{3 L} = \frac{n_{2} V}{L} = \frac{V}{4 L}$

$n_{1} = \frac{3}{8} n_{2} = \frac{1}{4}$ Which are not integer so not possible

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