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PhysicsSound WaveBeatsMedium2 minPYQ_2020

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The wavelengths of two notes in the air are $\frac{36}{195} m$ and $\frac{36}{193} m$ . each note produces $10$ beats per second separately with a third note of fixed frequency. The velocity of sound in air in $m s^{- 1}$ is

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Answer:

Solution:

Beat frequency= $v_{1} ~ v_{2}$

Let the frequency of third note be $n$ .

Then,

$\frac{195 v}{36} - n = 10 \dots (i)$

And

$n - \frac{193 v}{36} = 10 \dots (i i)$

Adding Eqs. (i) and (ii)

$\frac{v}{18} = 20$

$⟹ v = 360 m s^{- 1}$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Beats

⏱ 2mℹ️ Source: PYQ_2020

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